\DocumentMetadata{tagging = on} \documentclass{ltx-talk} \IfFontExistsTF{Pennstander-Regular.otf}{ \setmainfont{Pennstander-Regular.otf} \setmathfont{PennstanderMath-Regular.otf} } {} \title{The Quadratic Formula} \subtitle{$ax^{2} + bx + c = 0$} \author{David} \institute{The \LaTeX{} Project} \date{2025-12-06} \begin{document} \maketitle \begin{frame} \frametitle{Completing the Square} \large First, complete the square \begin{itemize}[action-spec = <+->, item-vspace = 20pt, begin-vspace = 20pt] \item $ax^{2} + bx +c=0$ \item $x^{2} + \frac{b}{a}x + \frac{c}{a} = 0$ \item $x^{2} + \frac{b}{a}x + \bigl(\frac{b}{2a}\bigr)^{2} = -\frac{c}{a} + \bigl(\frac{b}{2a}\bigr)^{2}$ \item $\bigl(x + \frac{b}{2a}\bigr)^{2} = -\frac{c}{a} + \bigl(\frac{b}{2a}\bigr)^{2}$ \end{itemize} \end{frame} \begin{frame} \frametitle{Solve for~$x$} \large Now, solve for~$x$ \begin{itemize}[action-spec = <+->, item-vspace = 20pt, begin-vspace = 20pt] \item $\bigl(x + \frac{b}{2a}\bigr)^{2} = -\frac{c}{a} + \bigl(\frac{b}{2a}\bigr)^{2}$ \item $x + \bigl(\frac{b}{2a}\bigr) = \pm \sqrt{-\frac{c}{a} + \bigl(\frac{b}{2a}\bigr)^{2}}$ \item $x = -\bigl(\frac{b}{2a}\bigr) \pm \sqrt{-\frac{c}{a} + \bigl(\frac{b}{2a}\bigr)^{2}}$ \item $\displaystyle x = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}$ \end{itemize} \end{frame} \begin{frame} \frametitle{The Quadratic Formula} \large The solution of the quadratic equation. \[ ax^{2} + bx + c = 0 \] where~$a$ is non-zero, is given by the formula \[ x = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a} \] \end{frame} \end{document}